Hi Walter,
Is it possible to get bottom (last) generation in genogram?
I need to display one node that should not have any links connected nothing but unlinked nodes. Those links are displayed at the below of last generation of genogram.
Is it possible?
Thanks,
Prameela.D
Yes. Here’s a stand-alone example of a LayeredDigraphLayout that puts all of the singleton nodes in a column to the right or a row underneath the main layout.
function ArrangedLayeredDigraphLayout() {
go.LayeredDigraphLayout.call(this);
this.arrangementSpacing = 50; // some space between the sub graphs
}
go.Diagram.inherit(ArrangedLayeredDigraphLayout, go.LayeredDigraphLayout);
ArrangedLayeredDigraphLayout.prototype.doLayout = function(coll) {
var net = this.makeNetwork(coll);
var subnets = net.splitIntoSubNetworks();
var initorig = this.arrangementOrigin.copy();
var orig = this.initialOrigin(initorig).copy();
var diagram = this.diagram;
diagram.startTransaction();
// layout each subnetwork
// you could sort these in a different order, if you like
var lay = this;
subnets.each(function(n) {
lay.network = n;
lay.arrangementOrigin = orig;
go.LayeredDigraphLayout.prototype.doLayout.call(lay, coll);
var bnds = diagram.computePartsBounds(n.findAllParts());
if (lay.direction === 0 || lay.direction === 180) {
orig.x += bnds.width + lay.arrangementSpacing;
} else {
orig.y += bnds.height + lay.arrangementSpacing;
}
})
// now layout any singleton nodes left over from splitIntoSubNetworks()
// you could also sort these in a different order
net.vertexes.each(function(v) {
var node = v.node;
if (node !== null) {
node.move(orig);
var bnds = node.actualBounds;
if (lay.direction === 0 || lay.direction === 180) {
orig.y += bnds.height + lay.arrangementSpacing;
} else {
orig.x += bnds.width + lay.arrangementSpacing;
}
}
});
this.arrangementOrigin = initorig;
diagram.commitTransaction("ArrangedLayeredDigraphLayout");
};
You just need to adapt this code by putting its doLayout into your custom GenogramLayout.
Where to call the function ArrangedLayeredDigraphLayout?
It’s not a function – it’s a class. Please read and understand the code before adapting it.
Please correct my words, Shall I add your code in my genogram code as it is? and by using which variable I can get last generation number.
I thought your initial post in this topic was asking about how to position an unlinked node in a row below all of the other nodes and links. Is that not the case? What I gave you was a custom LayeredDigraphLayout that does that for any number of nodes that have no connected links. But you already have a custom LayeredDigraphLayout, so you need to merge the doLayout method into your code.
